1000 -- A + B Problem
Time Limit :1000 MS Memory Limit :65536 KB
Accepts : 1508 Submits : 2479
User Accepts : 1010 User Submits : 1060
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Description
Calculate A + B

Input
Two integer A B, 1 <= A, B <= 1000

Output
A + B

Sample Input
1 2

Sample Output
3

Hint
Q: Where are the input and the output?

A: Your program shall always read input from stdin (Standard Input) and write output to stdout (Standard Output). For example, you can use 'scanf' in C or 'cin' in C++ to read from stdin, and use 'printf' in C or 'cout' in C++ to write to stdout.

You shall not output any extra data to standard output other than that required by the problem, otherwise you will get a "Wrong Answer".

User programs are not allowed to open and read from/write to files. You will get a "Runtime Error" or a "Wrong Answer"if you try to do so.

Here is a sample solution to problem 1000 using C++/G++: 
 

#include <iostream>
using namespace std;
int main()
{    
	int a,b;
	cin >> a >> b;
	cout << a+b << endl;
	return 0;
}
It's important that the return type of main() must be int when you use G++/GCC,or you may get compile error.

Here is a sample solution to problem 1000 using C/GCC:
#include <stdio.h>
int main(){    
	int a,b;    
	scanf("%d %d",&a, &b);    
	printf("%d
",a+b); 
	return 0;
}


Here is a sample solution to problem 1000 using Java:

Now java compiler is jdk 1.5, next is program for 1000

import java.io.*; import java.util.*; public class Main{ public static void main(String args[]) throws Exception { Scanner cin=new Scanner(System.in); int a=cin.nextInt(),b=cin.nextInt(); System.out.println(a+b); } } Here is a sample solution to problem 1000 using Pascal:
program p1000(Input,Output); var a,b:Integer; begin Readln(a,b); Writeln(a+b); end.

Source

Classical Problem
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